Coding Help Needed Nothing Big I Hope

[ryanhouston]

Hello i am using the following code to display a message if a variable is not equal to 1 or 2 if this is not equal it displays an error but if it is equal it does nothing. The code below shows the error never mind what the value is this isn't what i want.

$display = 1;

if ($display !== 1 || 2)
    {
    echo "error";
    }

[shannonlp]

Try this

<code>

$display_test = 1;

switch ($display_test) {
case 1:
echo 'no error';
break;

case 2:
echo 'no error';
break;

default:
echo 'error';
break;
}
</code>

[Jean-Luc]

Or try this:

$display = 1;

if ( $display != 1 && $display != 2 )
    {
    echo "error";
    }

Jean-Luc

[ryanhouston]

Originally Posted by Jean-Luc

Or try this:

$display = 1;

if ( $display != 1 && $display != 2 )
    {
    echo "error";
    }

Jean-Luc

Thank you very much for this piece of code do you have msn ??